HEIDENHAIN TNC 151 Q - Page 63

Example showing the formation of the BCC
bit No.
P”) 6 5 4
3 2 1 .O
1. Character SOH
1 0 0 0
0 0 0 1
2. Character %
1 0 1 0
0 1 0 1
3. Character 1
1 0 1 1
0 0 0 1
4. Character 5
0 0 1 1
0 1 0 1
5. Character E
1 1 0 0
0 1 0 1
6. Character ETB
0 0 0 1
0 1 1 1
-
BCC
1
I
’ 1
0 l-c 1 0
*)P = bit for character parity (cross parity)
All bits are completed for an even length parity with the BCC (the only exception is the bit for character
parity).
Machine parameters determining the interface signals for “Transfer blockwise”
The determination of entry values is described under parameter 71.
Parameteir
No.
bit
218 0...7 % or ASCI l-character.
8...15
m-----J-CT---
( 8...15
224
Function
Transmitted within command block for data input
before program number.
E or ASCI l-character.
Transmitted within command block for data input
after program number.
% or ASCI l-character.
Transmitted within command block for data output
before program number.
A or ASC I l-character.
Transmitted within command block for data output
after program number.
-ETB or substitute character (decimal code 1 - 47)
SOH or substitute character (decimal code 1 -. 47)
___
ACK or substitute character (decimal code 1 -- 47)
NAK or substitute character (decimal code 1 -- 47)
EOT or substitute character (decimal code 1 -. 47)
Entry values
for:
% and E:
17701
% and A:
16677
ETB and SOH:
279
ACK and NAK
5382
EOT
4
63