(5) Appliances without any indication as to power consumption
Some appliances have no indication as to power consumption; but instead the work load (output) is
indicated. In such a case, power consumption is to be worked out according to the numerical formula
mentioned below.
(Output of electrical appliance) = (Power consumption)
(Efficiency)
Efficiencies of some electrical appliances are as follows:
Single-phase motor . * * . . . . a . . . - . . * . .
0.6 - 0.75
The smaller the motor, the
Three-phase motor
. . - . . . . . . - - - * - . .
0.65 - 0.9
It-
lower the efficiency.
Fluorescent lamp - - - * . . . . * . . . - a e . . . .
0.7 - 0.8
Example 1:
A 40W fluorescent lamp means that its luminous output is 40W. Its efficiency is 0.7 and
accordingly, power consumption will be 40 i 0.7= 57W. As explained in
item(2),
multiply
this power consumption value of 57W by 1.2 - 2 and you will get the figure of the necessary
capacity of a generator. In other words, a generator with a rated output of 1000Wcapacity
can light nine to fourteen 40W fluorescent lamps.
Example
2: Generally speaking, a 400W motor means that its work load is 400W. Efficiency of this
motor is 0.7 and power consumption will be 400 t 0.7= 57OW. When this motor is used for
a motor-driven tool, the capacity of the generator should be multipled by 1.2 to 3 and 570W
as explained in the
Item(3).
MODEL
Frequency
lncandesent lamp,
heater, etc.
RGXl800 RGX2400 RGX3500 RGX5500
I
50Hz ’ 60Hz i 50Hz 60Hz 50Hz 60Hz
50Hz 1 60Hz
13oow 15oow
17oow 2ooow 2500W 3ooow j 4400w
4800W
Fluorescent lamp,
approx.
approx. approx.
approx. i approx.
1300w ; 17oow ZE
approx. approx.
mercury lamp, etc.
j 9oow
1 ooow
11OOw
: 2800W 3200W
Motor-driven tool,
general-purpose motor.
approx.
; approx. ! approx.
approx.
approx. approx. approx. approx.
etc.
800W / 9OOW 1OOOW
12oow 15oow
18OOW
2600W ; 2900W
I
Water pump.
compressor, etc.
approx.
! approx. approx.
450w 1 5oow
approx.
! 4oow 600W
approx. ’ approx. ; approx.
approx.
750w 9oow 1300w 1 1400w
I
Table 7-1
- 41 -
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