EasyManua.ls Logo

TCL TAC-09CHSC

TCL TAC-09CHSC
138 pages
To Next Page IconTo Next Page
To Next Page IconTo Next Page
To Previous Page IconTo Previous Page
To Previous Page IconTo Previous Page
Loading...
Example) By using the Mollier diagram of R-22, find the compression ratio, refrigeratiny effect, work of compres-
sion, calorie of condensation, circulation amount of refrigerant, coefficient of performance, and refriger-
ating effect per 1KW.
Condensation pressure : Pd = 18.1kg/cm
2
abs
Evaporation pressure : Ps = 6.5kg/cm
2
abs
Compression ratio : Pr = Pc/Pe = 18.1/6.5 = 2.78
Enthalpy : iA = 148.5kcal/kg
iB = 158.5kcal/kg
iC = 110kcal/kg
iD = 110kcal/kg
iC' = iD'= 112kcal/kg
iE = 148kcal/kg
Accordingly, Refrigerating effect : q1 = iA - iD = 148.5 - 110 = 38.5 [kcal/kg]
Work of compression : A1 = iB - iA = 158.5 - 148.5 = 10 [kcal/kg]
Calorie of condensation : q2 = iB - iC = 158.5 - 110 = 48.5 [kcal/kg]
Circulation amount of refrigerant : G=Q/q1 = 3320/38.5 = 86.2 [kg/h.RT] (per 1 Refrigerating Ton)
COP : q1/A1 = 38.5/10 = 3.85
Refrigerating effect per 1KW : k = 860 x 3.85 = 3311 [kcal/h. KW]
D
E
A
C
C'
B
D'
8°C
15.0
3.0
38°C
46°C
16°C
40°C
75°C
110 112 148 148.5 158.5
0.0016m /kg
3
0.0024m /kg
3
Absolute Pressure(kg/cm2 abs)
14

Table of Contents

Related product manuals