frequency of V
ts
= 50 Hz
I
50s
= 0 A
I
tfs
= 0 A
• State 2: main test step.
Define the following three-phase symmetrical quantities (the phase angle is
related to phase L1):
V V
V
V
V
ts t RvsZ
VT s
VT p
= × × = × × =1 1 1 1 5899
0 1
13 8
47 02. .
.
.
.
,
,
,
EQUATION14069 V1 EN (Equation 73)
29.60
arctan 180 arctan 180 90.56
0.29
ts
ReverseX
V
ReverseR
Ð = - ° = - ° = - °
æ ö æ ö
ç ÷ ç ÷
è ø è ø
EQUATION14068 V1 EN (Equation 74)
frequency of V
ts
= 50 Hz
I I
I
I
A
s
CTs
CTp
50 50
10459
1
9000
1 162= × = × = .
EQUATION14059 V1 EN (Equation 75)
∠I
50s
= 0º
frequency of I
50s
= 50 Hz
It I
I
I
A
fs
CTs
CTp
tf= × = × =10459
1
9000
1 162.
EQUATION14062 V1 EN (Equation 76)
∠I
tfs
= 180º
frequency of I
tfs
= 50.5 Hz
Expected result: the protection function does not issue either start or trip.
After each test it is possible to download and study the related disturbance recording.
1MRK502053-UEN B Section 12
Testing functionality by secondary injection
Generator protection REG670 2.0 IEC 139
Commissioning manual
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