2-33
Integration Calculation Precautions
• Because numerical integration is used, large error may result in calculated integration
values due to the content of
f(x), positive and negative values within the integration interval,
or the interval being integrated. (Examples: When there are parts with discontinuous
points or abrupt change. When the integration interval is too wide.) In such cases, dividing
the integration interval into multiple parts and then performing calculations may improve
calculation accuracy.
• In the function
f(x), only X can be used as a variable in expressions. Other variables (A
through Z excluding X,
r, ) are treated as constants, and the value currently assigned to
that variable is applied during the calculation.
• Input of “
tol” and closing parenthesis can be omitted. If you omit “tol,” the calculator
automatically uses a default value of 1 × 10
–5
.
• Integration calculations can take a long time to complete.
• You cannot use a first derivative, second derivative, integration, Σ, maximum/minimum value,
Solve or RndFix calculation expression inside of an integration calculation term.
• In the Math input/output mode, the tolerance value is fixed at 1 × 10
–5
and cannot be changed.
k Σ Calculations [OPTN]-[CALC]-[Σ(]
To perform Σ calculations, first display the function analysis menu, and then input the values
using the syntax below.
<Math input/output mode>
K4(CALC)6(g)3(Σ( )
ak e k e
α
e
β
or
4(MATH)6(g)2(Σ( )
ak e k e
α
e
β
<Linear input/output mode>
K4(CALC)6(g)3(Σ( )
ak , k ,
α
,
β
, n )
(
n: distance between partitions)
Example To calculate the following:
Use
n = 1 as the distance between partitions.
AK4(CALC)6(g)3(Σ( )a,(K)
x-da,(K)+fe
a,(K)ecegw
Calculation Precautions
• The value of the specified variable changes during a Σ calculation. Be sure to keep separate
written records of the specified variable values you might need later before you perform the
calculation.
• You can use only one variable in the function for input sequence
ak.
β
Σ
(
a
k
,
k
,
α
,
β
,
n
)
=
Σ
a
k
=
a
α
+
a
α
+1
+........+
a
β
k =
α
β
Σ
(
a
k
,
k
,
α
,
β
,
n
)
=
Σ
a
k
=
a
α
+
a
α
+1
+........+
a
β
k =
α
6
Σ
(
k
2
–3
k
+5)
k = 2
6
Σ
(
k
2
–3
k
+5)
k = 2
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