McElroy No.2LC - Determine Fusion Force

Variable Definitions
O.D. = Outside Diameter
t = Wall Thickness
∏ = 3.1416
SDR = Standard Dimensional Ratio
IFP = ManufacturerÊs Recommended
Interfacial Pressure
Formulas
O.D.
t = ------------
SDR
AREA = (O.D. - t) x t x ∏
FORCE = AREA x IFP
REQUIRED FORCE = (O.D. - t) ï t ï ∏ ï IFP + DRAG
Example
Pipe Size = 4" SDR 11
O.D. of Pipe = 4.5"
SDR of Pipe = 11
Recommended Interfacial Pressure = 75 PSI
Using a Model PitBull No.14 Fusion Unit
O.D. 4.5
t = ------------- = --------------- = 0.409
SDR 11
REQUIRED FORCE = (O.D. - t) ï t ï ∏ ï IFP + DRAG
REQUIRED FORCE = (4.5 - .409) ï .409 ï 3.1416 ï 75 + DRAG = 394 + DRAG
From Table:
30 ft/lbs of Torque = 330 lbs Force
and
40 ft/lbs of Torque = 435 lbs Force
Interpolating between these two values give approximately
36 ft/ lbs Torque.
FUSION FORCE = 36 ft/lbs + Drag (measured in ft/lbs)
TX02482-9-22-09-
6 - 1
Determining Fusion Force
Torque Wrench No.2LC PitBull No.14
Reading Jaw Axial Force Jaw Axial Force
(Ft Lb) (Lb) (Lb)
10 70 115
20 135 215
30 200 330
40 260 435
50 320 545
60 400 660
70 480 780
80 550 915
90 635 1025
100 690 1140
PH01885-7-25-00
This table is only valid when using a torque
wrench and adapter used as shown in the pic-
ture above. A 1/2" drive 100 ft-lb 15.0" torque
wrench with the torque wrench adapter. Using a
torque wrench of a different length will result in
different forces from the torque reading.