250
[SwitchC] bgp 200
[SwitchC-bgp] peer 193.1.1.1 as-number 100
[SwitchC-bgp] peer 195.1.1.1 as-number 200
[SwitchC-bgp] ipv4-family unicast
[SwitchC-bgp-ipv4] peer 193.1.1.1 enable
[SwitchC-bgp-ipv4] peer 195.1.1.1 enable
[SwitchC-bgp-ipv4] quit
[SwitchC-bgp] quit
# Configure Switch D.
[SwitchD] bgp 200
[SwitchD-bgp] peer 194.1.1.2 as-number 200
[SwitchD-bgp] peer 195.1.1.2 as-number 200
[SwitchD-bgp] ipv4-family unicast
[SwitchD-bgp-ipv4] peer 194.1.1.2 enable
[SwitchD-bgp-ipv4] peer 195.1.1.2 enable
[SwitchD-bgp-ipv4] quit
[SwitchD-bgp] quit
4. Configure attributes for route 1.0.0.0/8, making Switch D give priority to the route learned from
Switch C:
{ (Method 1.) Configure a higher MED value for the route 1.0.0.0/8 advertised from Switch A to
p e e r 19 2.1.1.2:
# Define an ACL numbered 2000 to permit route 1.0.0.0/8.
[SwitchA] acl number 2000
[SwitchA-acl-basic-2000] rule permit source 1.0.0.0 0.255.255.255
[SwitchA-acl-basic-2000] quit
# Define two routing policies, apply_med_50, which sets the MED for route 1.0.0.0/8 to 50,
and apply_med_100, which sets the MED for route 1.0.0.0/8 to 100.
[SwitchA] route-policy apply_med_50 permit node 10
[SwitchA-route-policy-apply_med_50-10] if-match ip address acl 2000
[SwitchA-route-policy-apply_med_50-10] apply cost 50
[SwitchA-route-policy-apply_med_50-10] quit
[SwitchA] route-policy apply_med_100 permit node 10
[SwitchA-route-policy-apply_med_100-10] if-match ip address acl 2000
[SwitchA-route-policy-apply_med_100-10] apply cost 100
[SwitchA-route-policy-apply_med_100-10] quit
# Apply routing policy apply_med_50 to the route advertised to peer 193.1.1.2 (Switch C),
and apply_med_100 to the route advertised to peer 192.1.1.2 (Switch B).
[SwitchA] bgp 100
[SwitchA-bgp] ipv4-family unicast
[SwitchA-bgp-ipv4] peer 193.1.1.2 route-policy apply_med_50 export
[SwitchA-bgp-ipv4] peer 192.1.1.2 route-policy apply_med_100 export
[SwitchA-bgp-ipv4] quit
[SwitchA-bgp] quit
# Display the BGP routing table on Switch D.
[SwitchD] display bgp routing-table ipv4
Total number of routes: 2
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