Second, we connect a resistor with the battery and measure its voltage, in our case we will
connect a 510 Ξ© resistor.
The measured voltage in this figure is 8.55 V DC.
Third, we will do some calculations using Ohmβs law.
β Calculate the current passing through the resistor:
π
π
π
= πΌ
8.55 π
510 Ξ©
= 0. 0168 π΄ = 16. 8 ππ΄
β Subtract the voltage of the battery from the voltage of the resistor:
π΅
π
β π
π
= π΅
π
π
8. 95 π β 8. 55 π = 0. 40 π
β Now, we have the current and the voltage on the internal resistance, so we can calculate the
value of the internal resistor:
π
πΌ
= πΌ
π΅π
0.40 π
0.0168 π΄
= 23. 81 Ξ©
39
Mastering the Art of Measurement (DM501D Digital Multimeter) r.01 www.plusivo.com