and all 8 analog inputs are being used. Further assume all 32 digital I/O points will be on with the
LEDs enabled. Input will not be boosted in the 5604.
5V Current (mA) DC Input Current (mA)
5232 Controller
Board
500 0
5604 I/O Module
170 10 + 200
Total
670 210
The controller board has 1300mA available from the 5V supply. A minimum of 100mA is available
from the 24V supply. Additional current is available from the 24V supply when the 5V is not loaded
to its 1300mA maximum.
The total available 24V supply current is calculated as follows:
24V current = 80 + ((1300 – Total Current @ 5V) x 0.25)
=
257.5mA
where:
100 = Minimum current @ 24V
1300 = Maximum current @ 5V
Total Current @ 5V = Sum of 5V current required for system
0.25 = Derating factor is a constant
In this example, when 670mA is required at 5V, 257.5mA is available on the 24V supply on
connector P3. This is greater than the 210mA required by the integrated 5604 I/O module. The
Recommended AC Power Supply Configuration can therefore be used to power the SCADAPack
P4A controller.
4.2.5.2.2 Example 2
In this example there is a 5232 Controller board with a 5604 I/O Module and analog outputs
powered using a 12V battery such that 24V is generated using the 12/24 boost converter onboard the
5604 module. This 24V must be available for both analog outputs and all 8 of the analog inputs.
Also assume all 32 digital I/O points will be on with the LEDs enabled.
5V Current (mA) DC Input Current
5232 Controller
Board
500 See calculation.
5604 I/O Module
170 See calculation.
Total
670 See calculation.
The 5604 DC Input supply current is calculated as follows:
5604 DC Input Current = (24 x Total Current @ 24V) / (12 x 0.88)
= (24 x .20) / (12 x 0.88)) =
455mA
SCADAPack 32 Controller Hardware Manual
May 24, 2006
15
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