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Robin RGV2800 Service Manual

Robin RGV2800
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(5)
Appliances without any indication as
to
power
consumption
Some appliances have no indication as to power consumption; but instead the work load (output) is
indicated. In such a case, power consumption is to be worked out according to the numerical formula
mentioned below.
1
(Output
of
electrical appliance)
(Efficiency)
=
(Power consumpition)
Efficiencies
of
some electrical appliances are as follows
:
Single-phase motor
................................
0.6
to 0.75 The smaller the motor, the
Fluorescent lamp
...................................
0.7 to
0.8
(
lower
the
efficiency-
)
Example
1:
A
40W fluorescent lamp means that its luminous output is 40W. Its efficiency is 0.7 and
accordingly, power consumption will be 40
+
0.7= 57W.
As
explained in Item
(2),
multiply
this power consumption value of
57
W by
1.2
to
2
and you will get the figure of the neces-
sary capacity of a generator.
In
other words, a generator with a rated output of
lOOOW
capacity can light nine to fourteen
40
W
fluorescent lamps.
Example
2
:
Generally speaking, a 400
W
motor means that its work load is 400
W.
Efficiency of this
motor is 0.7 and power consumption will be 400+0.7=
570
W.
When this motor is used for
a motor-driven tool, the capacity
of
the generator should be multiple
of
570
W
by
1.2
to
3
as
explained in the Item
(3).
570
(W)
x
1.2 to
3
=
684
(W)
to
171
0
(W)
MODEL
RGV6100
RGV4lOO RGV2800
d
Frequency
60
H
I
I
lncandesent
lamp,
heater, etc.
I
2300
W
I
3600
W
1
48oow
I
Fluorescent
lamp,
Motor-
approx.
approx.
approx.
driven
tool,
general-porpose
I
1800W
I
2400W
I
Mercury
lamp,
etc.
approx.
approx.
approx.
1
800W
1
1600W
Pump,
compressor,
etc.
approx.
1100
w
850
W
550
W
approx.
approx.
Table.
7-7
-
24-

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Robin RGV2800 Specifications

General IconGeneral
BrandRobin
ModelRGV2800
CategoryPortable Generator
LanguageEnglish

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