Chapter 3 Calibration Procedures
Constant Current (CC) Verifications
57
3
6
Record the value displayed on the controller. This value should be within the
limit of (I
O
± 5 mA).
7
Program the output current to the full rated value (20.0 A)* or (7.0 A)* * by
sending the command:
CURR 20.0 (E3633A)
CURR 7.0 (E3634A)
8
Divide the voltage drop (DVM reading ) across the current monit oring resistor
(R
M
) by its resista nce to convert to amps and record this value (I
O
). This value
should be within the limit of (20 A ± 50 mA)* or (7A ± 24 mA)**.
9
Readback the output current over the remote interface by sending the
command:
MEAS:CURR?
10
Record the value displayed on the controller. This value should be within the
limit of (I
O
± 35 mA)* or (I
O
± 15.5 mA)**.
CC Load Effect (Load Regulation)
This test measures the immediate change in output current resulting from a
change in the load from full rated output voltage to short circuit.
1
Turn off the power supply and connect the output to tested as shown in
Figure 3-1 with the digital voltmeter connected across the 0.01
Ω
current
monitoring resi stor (R
M
).
2
Turn on the power supply. Select the 8V/20A* or 25V/7A** range, enable the
output, and set the display to the limit mode. When the display i s in the limit
mode, program the output voltage to the maxim um programm able value and
the output current to the ful l rated value (20. 0 A)* or (7.0 A)* *.
3
Set the voltage of the electronic load to (6.0 V)* or (23.0 V)** to operate it in
constant voltage mode since a voltage drop occurs on the load wires when
(20.0 A)* or (7.0 A)** flows on the load wires. Check that the
CC
annunciator
is on. If it is not, adjust the load so that the output voltage drops slightly. Record
the current reading by dividing the voltage reading on the digital voltmeter by
the resistance of the current monitoring resistor.
4
Operate the electronic load in short (input short) mode. Record the curr en t
reading immediately by dividi ng the vol tage reading on the digi tal voltm eter
by the resistance of the current monitori ng resistor. The difference between
the current readings in step (3) and (4) is the load regu lation current. The
difference of the readings durin g the i mm edi ate ch ange should be withi n the
lim it of (2.25 mA )* or (0.95 mA )** .
*For Agilent E3633A Model **For Agilent E3634A Model
To Next Page
Loading...
Need help?
General
