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HP 5528A

HP 5528A
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Model
55
2
8A
V.D
.L Compensation
Fa
c
tor
19
-6
EXA
MP
LE
:
Using the " standard"
conditions
,-
Humidity
=
50
% =
"1-1"
Pres
s
ure
(absolute) = 760 mm
Hg
=
"P
"
Temperature =
20
0
(
= "
T"
we
will
calculate the compensation factor, using the
Metric
formula for finding "N", and showing
all
our
work
.
O.0133T
~
0.266000000
0.81
7 - (
#'
) =
0.5
5
1000000
P X
10
II X (
#2
) =
0.000418760
0.00366
1
0T
-
0.073220000
1 + (
'5
)
~
1.073220000
(
'4
)/(
'6
)
~
0.932165595
0.3836391
X P X (li7) =
271.7875292
e Q,057267T =
3.143409969
1-1
X (
#9
) = 157.
1754985
3.
033
X
10
-3 X (
#10
)
::::
0.476737287
(
'8
)-
(
"'
)
~
271.3108159
(
#12
) +
10
e =
1000271.311
10
12
~
999728.7626
(
'13
)
c
~
(#14) - 999000 - 728.7626 - 728.8
(" I
(
'2
)
(
'3
)
(
'5
)
(
'6
)
(
'7
)
(li8) (
Save
)
(
'9
)
(
#10
)
(
",
)
(#12 )
(
013
)
(
"4
)
(
#15
)
(
for
comparison, the answer
we
were
looking
for in this example just happens
to
be
"
728
.8
")

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