Model
5528A
V.O.l.
Compensation
Facior
4.
CALCULATION OF EXACT
COMPENSATION
FACTOR
If the laser Measurement
Sys
l
em
is
being
operated
in an environ
men
l thai
is
not included in Ihe
tables
in
t
hi
s User's
Gu
id
e section, you can calculate the exact compenSJtion
fa
ctor by u
si
ng
the
following formulas to an accuracy of
0.1
ppm
.
CAUTION
The accur;,u:y of your
hser
System Measur
ement
is
ill
function of
your
ability to provide
it
with the
co
rrection compensation factor for
your
mea5Urcment conditions. When determining the com-
pen
sa
tion
fador
by
ulculation
rather thlln
by
using
the
com
-
fH!nsation
fllclor tllbles, the result you get depends on the
resolulion of the
equipment
on which you mllke your calculation
and on your ability to ofH!rale
it
withoul error.
You
will
be workins
with numbers that are very small and numbers that are very large;
even
the smallest error can have
ill
significant
effed
on
the
accuracy of your answer,
and
any error
Is
extremely dlfflc
uili
o
detect
or
(rillce
. We strongly suggest
thill'
you make a " practic
e"
run, using
vililues
from any
of
the
compensation value tables,
to
get
ill
feeling for
whillt
is
required.
In
the formulas below -
T
=
Ai
r Temperature
P
""
Air
Pressure
1-1
=
Re
lat
ive
Humidi
ty
C
""
Compcnsation Factor, to be
ente
r
ed
manually,
via
the
Measurement Display unit's
front-pancl
keys.
10
12
C =
--
-
999000
N+
10
6
where
"N"
is givcn
in
metric
and
English
sys
tems
by
-
Melric: T
in
degree
s Celsius, P
in
millimctrcs of mcrcury,
1-1
in
'X>
N
""
0
.3
836391 P X
[
1
+ 10 -6 P (0.817 - 0.0133T) ]
1 + 0
.OO366
10T
- 3.033 X
10
~
J
H
[c
0057627T]
English : T in degrees Farcnheit, P
in
inches of mercury.
1-1
in
'J{,
N
""
9.74443P X
[1
+ 10 -6 P (26.7 - O.l
B7T
) ] _ 1.089 X
10
-J H
[c
003201ST]
0.934915 + O
.OO20388T
19-5
To Next Page
Loading...
Need help?
General
