Mitsubishi A1SJH - Page 71

6. BASE UNIT AND EXTENSION CABLE
6 - 4
MELSEC-
A
(3) Calculation of the receiving-end voltage
01234567
I
0
V
0
I
1
V
1
I
2
V
2
I
3
V
3
I
4
V
4
I
5
V
5
I
6
V
6
I
7
V
7
I
CPU
V
CPU
AnSH
CPU
I
8
V
8
I
9
V
9
I
10
V
10
I
11
V
11
I
12
V
12
I
13
V
13
I
14
V
14
I
15
V
15
8 9 10 11 12 13 14 15
V
CPU
, V
0
to V
7
: Voltage drop of each slot of a main base unit
I
CPU
, I
0
to I
7
: Current consumption of each slot of a main base unit
V
8
to V
15
: Voltage drop of each slot of an extension base unit
I
8
to I
15
: Current consumption of each slot of an extension base unit
(a) Calculation of voltage drop of a main base unit (A1S32B, A1S33B,
A1S35B, A1S38B)
Each slot of a main base unit has a resistance of 0.007
Ω
.
Calculate the voltage drop of each slot, to obtain the total voltage drop of
a main base unit.
Current consumption of CPU module
•
A1SJHCPU(S8), A1SHCPU : 0.3(A)
•
A2SHCPU(S1) : 0.4(A)
1) Voltage drop of a CPU module : V
CPU
V
CPU
= 0.007
×
(I
cpu
+ I
0
+ I
1
+ I
2
+ I
3
+ I
4
+ I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
2) Voltage drop of slot 0 : V
0
V
0
= 0.007
×
(I
0
+ I
1
+ I
2
+ I
3
+ I
4
+ I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
3) Voltage drop of slot 1 : V
1
V
1
= 0.007
×
(I
1
+ I
2
+ I
3
+ I
4
+ I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
4) Voltage drop of slot 2 : V
2
V
2
= 0.007
×
(I
2
+ I
3
+ I
4
+ I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
5) Voltage drop of slot 3 : V
3
V
3
= 0.007
×
(I
3
+ I
4
+ I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
6) Voltage drop of slot 4 : V
4
V
4
= 0.007
×
(I
4
+ I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
7) Voltage drop of slot 5 : V
5
V
5
= 0.007
×
(I
5
+ I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
8) Voltage drop of slot 6 : V
6
V
6
= 0.007
×
(I
6
+ I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
9) Voltage drop of slot 7 : V
7
V
7
= 0.007
×
(I
7
+ I
8
+ I
9
+ I
10
+ I
11
+ I
12
+ I
13
+ I
14
+ I
15
)
10) Total voltage drop of a main base unit : V
K
V
K
=V
CPU
+ V
0
+ V
1
+V
2
+ V
3
+ V
4
+ V
5
+ V
6
+ V
7
)