31
SC-1
Using C (from Equation2) and g
d2
(from Equation4) values, Equation1 can be solved for
theflux:
Equation9
F
vapor
=
ρ
D
vapor
d
2
⎝
⎜
⎜
⎠
⎟
⎟
1
P
atm
h
r1
e
s
(T
a1
) − h
r 2
e
s
(T
a 2
)
⎡
⎣
⎤
⎦
Now that F
vapor
has been solved, the stomatal conductance (g
s
) can be determined. This
requires some assumptions. First, the RH within the leaf tissue is assumed to be 1.0, so
Equation2 becomes
Equation10
=C
P
sa
leaf
Second, all conductance values are assumed to be in series, so the flux is constant between
any two nodes. Third, the temperature of the leaf is equal to the temperature of the first RH
sensor (the sensor block head is aluminum to eliminate the temperature difference).
These assumptions mean Equation1 can be written for node 1 and the leaf node
(Equation11, Equation12) and then set equal to Equation9 (Equation13).
Equation11
=−
+
sdvapor 1leaf 1
Equation12
F
vapor
= g
s+ d1
1
P
⎝
⎜
⎠
⎟
e
s
(T
a1
)(1− h
r
)
⎡
⎣
⎤
⎦
Equation13
g
s+ d1
P
atm
e
s
(T
a1
)(1− h
r
)
⎡
⎣
⎤
⎦
=
1
P
atm
ρ
D
d
2
⎝
⎜
⎠
⎟
h
r1
e
s
(T
a1
) − h
r 2
e
s
(T
a2
)
⎡
⎣
⎤
⎦
Solving for g
s+d1
,
Equation14
g
s+ d1
=
ρ
D
d
2
⎝
⎜
⎠
⎟
h
r1
e
s
(T
a1
) − h
r 2
e
s
(T
a2
)
⎡
⎣
⎤
⎦
e
(T
)(1− h
)
Then solve for g
s
using the rule for series combination of conductance (Equation15).
Equation15
=−
gg g
Hence,
Equation16
g
s
=
s
a1
r1
2
ρ
!
D h
e
(T
) − h
e
(T
)
⎡
⎤
−
1
ρ
!
D