Lumel ND30PNET - Page 39

ND30PNET-09 - User's Manual
38
Table 16
Address
of register
Ope-
ration
s
Range
Description
Default
4000
RW
0…9999
Protection - password
0
4001
RW
0 .. 1
Connections layout
0 - 3Ph/4W
1 - 3Ph/3W
2 - 1Ph/2W
0
4002
RW
0 .. 2
Voltage at terminal 2:
0 - voltage of the first phase L1
1 - voltage of the second phase L2
2 - voltage of the third phase L3
0
4003
RW
0 .. 2
Voltage at terminal 5:
0 - voltage of the first phase L1
1 - voltage of the second phase L2
2 - voltage of the third phase L3
1
4004
RW
0 .. 2
Voltage at terminal 8:
0 - voltage of the first phase L1
1 - voltage of the second phase L2
2 - voltage of the third phase L3
2
4005
RW
0..5
Current at terminals 1,3:
0 - current of the first phase I
L1
1 - reversed current direction of phase L1: -I
L1
2 - current of the second phase I
L2
3 - reversed current direction of phase L2: -I
L2
4 - current of the third phase I
L3
5 - reversed current direction of phase L3: -I
L3
0
4006
RW
0..5
Current at terminals 4,6:
0 - current of the first phase I
L1
1 - reversed current direction of phase L1: -I
L1
2 - current of the second phase I
L2
3 - reversed current direction of phase L2: -I
L2
4 - current of the third phase I
L3
5 - reversed current direction of phase L3: -I
L3
2
4007
RW
0..5
Current at terminals 7,9:
0 - current of the first phase I
L1
1 - reversed current direction of phase L1: -I
L1
2 - current of the second phase I
L2
3 - reversed current direction of phase L2: -I
L2
4 - current of the third phase I
L3
5 - reversed current direction of phase L3: -I
L3
4
4008
RW
0.1
Current input range: 1A or 5 A: 0 - 1 A, 1 - 5 A
1
4009
RW
0.1
Voltage input range:
0 – 3 x 57,7/100 V; 1 – 3 x 230/400 V (version 1)
0 – 3 x 110/190 V; 1 – 3 x 400/690 V (version 2)
1
4011
RW
0..65535
Primary voltage of transformer, two younger bytes
100
4012
RW
1 .. 10000
Secondary voltage of transformer x 10
1000
4013
RW
1 .. 20000
Primary current of transformer
5
4014
RW
1 .. 1000
Secondary current of transformer
5
4015
RW
0...2
Averaging time of active power P Demand, apparent
power S Demand,
current I Demand
0 – 15, 1- 30, 2- 60 minutes
0