ASDA Series Application Note Introduction of PR Operation
March, 2015
1-57
Result:
Figure 1.75 shows the result after PR group is carried out in Example 5.
PR
#1
Pos it i on (3)
D=0 S= 20.0 rpm
20 000 0 P UU, IN C
PR
#2
(I)
Jump
DLY=0
PR#10
PR
#10
(I)
Write
DLY= 5000
P5- 55 =10
PR
#11
(I)
Pos ition (3)
D=0, S=100.0 rpm
30 000 0 PU U, I NC
PR
#12
(I)
Write
DLY = 0
P5-55=12
(B ) 1ms
Command Group
(A) 1ms
Command Group
,
Figure 1.75 Output of PR Example 5 PR
See Figure 1.75, from t = T to t = 4+T sec, motor operates according to PR#1’s command.
Because PR#10 has set delay time of 5 sec., PR#11’s command will be executed after
t = 5+T sec.. From t = T to 5+T sec., P5-55 = 10. After 5+T second, P5-55 = 12.
21.2
21.2
10
10
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