3 Functions of Devices in DVP-PM
DVP-PM Application Manual
3-60
Total number of pulses required:
100,000
B
A
P(I)
B
P(I)
=×==
pulses
2. Operation speed V(I): 6 (cm/min) = 60,000/60 (um/sec)
444344421
444344421
43421
pulse/sec PPS,
A
1
B
Time
pulses of Number
pulses of Number
Revolution
Revolution
Distance
Time
Distance
uency)Speed(Freq ××==
Calculate the by the positioning controller
Frequency (PPS)
B
A
V(I)×= = 000,10=
100
000,1
×
60
000,60
PPS
y Example 3:
b[1:0] = 01
= 10, 11 @ Combined unit: unit for position: um; unit for speed: pulse/sec (PPS)
Assume:
D1818 (D1898/D1978) = 2,000 (Pulse/REV), D1820 (D1900/D1980) = 100 (um/REV), target position
P(I): 10,000 (um), and operation speed V(I): 10K (PPS). Solve the number of pulses required by pulse
instruction of the positioning controller.
Solution
:
Total number of pulses required
200,000
B
A
P(I)
B
P(I)
=×==
pulses
 b2 and b3 of D1816 (D1896, D1976, D2056): setting of multiplication of position data
The position data, i.e. zero point position (HP), target position (I) (P(I)), target position (II) (P(II)), current position
(CP), have to be multiplied by the multiplication values listed in the table below.
b3 b2 Multiplication
0 0 Position data × 10
0
0 1 Position data × 10
1
1 0 Position data × 10
2
1 1 Position data × 10
3
b4 and b5 of D1816 (D1896, D1976, D2056): pulse output type
b5 b4 Pulse output type (positive logic) Explanation
0 0
FP forward pulse s
RP r eve rse puls es
Double-phase
0 1
FP pulses
RP d irecti on (DIR)
Forward running
Reverse running
Single-phase
1 0
FP A-phase pulses
A/B phase