In the above example, make the following assumptions:
• An interpolated encoder is used.
• The maximum speed of the motor remains 10,000 rpm.
• The motor is equipped with an interpolated encoder with 2048 analog
sine/cosine periods per mechanical revolution.
• The interpolation x32 (CA[31]=5) is used.
• The feedback resolution is formed as
revcounts /655362*2048
5
= .
The expected minimum encoder (analog sine/cosine signals without interpolation)
transition time is:
sec4.732
000,10*4*2048
minsec/60
n
rpm
=
The encoder pulse time (sine/cosine signal cutting by hardware comparator) is
calculated as
sec11.183
4
sec4.732
n
n
=
and because of the CPU clock frequency,
the minimum required encoder signal stable time should be set to 200 nsec (i.e.
EF[ ] = 1).
Attributes: Type: Parameter, Integer
Source: Program, RS-232, CANopen
Restrictions: None
Default values: 0 (RS), Non-volatile
Range: [0...127]
Index range: [1, 2]
Unit modes: All
Activation: Immediate
SimplIQ Command Reference Manual Alphabetical Listing
MAN-SIMCR (Ver. 4.5)
3-46
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