EasyManua.ls Logo

Delta ME300 Series

Delta ME300 Series
457 pages
To Next Page IconTo Next Page
To Next Page IconTo Next Page
To Previous Page IconTo Previous Page
To Previous Page IconTo Previous Page
Loading...
Chapter 12 Description of Parameter Settings
ME300
12.1-12-7
As shown in the image below, a four-pole motor turntables diameter = r and its rotation speed =
n (RPM).
Example 01:
When the motor turntable is rotating at 50 Hz, Pr.00-22 =2 (motor stops by simple positioning),
Pr.12-26=50 Hz (Simple Positioning Stop Frequency 6), and its corresponding Pr.12-34 =2 seconds
(Delay Time of Simple Positioning Stop 6) , the deceleration time is 10 seconds for decreasing from
50 Hz to 0 Hz.
When STOP command is given, Simple Positioning Stop is activated, its rotation speed is
n = 120 x 50 / 4 (revolution / minute) = 25 (revolution / second).
Number of revolutions of motor turntable = (25 x (2 + 12)) / 2 = 175 (revolutions)
Therefore, the distance travelled by the motor after the STOP command is given = number of
revolutions x circumference = 175x 2 π r. It means the turntable returns to the top after 175
revolutions.
Example 02:
If the turntable rotates at 1.5 Hz, Pr.12-22 = 10 Hz (Simple Positioning Stop Frequency 2), Pr.12-
21 = 0 Hz, and Pr.12-30 =10 seconds (Delay Time of Simple Positioning Stop 2), then the
deceleration time is 40 seconds for decreasing from 60 Hz to 0 Hz.
The delay time to stop of 1.5 Hz is 1.5 seconds, the deceleration time is 1 second for decreasing
from 1.5 Hz to 0 Hz.
When STOP command is given, Simple Positioning Stop is activated, its rotation speed is
n = 120 x 1.5 / 4 (revolution / minute) = 1.5 / 2 (revolution / second).
Number of revolutions of motor turntable = (1.5/2 x (1.5 + 2.5)) / 2 = 1.5 (revolutions)
Therefore, the distance travelled by the motor after the STOP command is given = number of
revolutions x circumference = 1.5x 2 π r. It means the turntable stopped after 1.5 revolutions.

Table of Contents

Related product manuals