IBM 7090 - Page 89

SR (9-35)-
ADM(OO)
2.13.21.1
From Fig 5.3-26A
On (AC (9-35) = 0)
Turn On T2
A10(Dl)
2.10.3S.1
L Time
OBJECTIVES:
2nd Step
2.10.42.1
Comp
AC(Q-35)
_AD AO(D3)
1. Test for Quotient Equal to
lor More.
Set AC(s)
Plus A 1 O(Dl)
2.13.91.1
AD (Q-35)
AC A10(D1)
2.13.31.1
(Reset AC)
To I Time - Fig 5.3-26D
Turn Off FP
Tgr A2(D1)
2.10.29.1
AC(Q-35)-
AD A4(D3)
2.13.24.1
AD (Q-35)-
AC A2(Dl))
2.13.31.1
Carry-
AD(S) M(OO)
2.13.27.1
(Char Increased by
One; Quotient
Overflow is Possible)
(Dividend now is Complement Form
for Reduction Cycles)
Step SC
A7(D1)
2.13.71.1
FP Shift Lt
A7(Dl)
2.12.42.1
To L Time 3rd Step - Fig 5.3-26C
FIGURE 5.3-26B. FDH + 0240
88
Sh AC (10-35)
MQ(2-35) Lt
2.12.34.1
2.12.42.1
Turn On
9 Ov Tgr
2.10.39.1