Continental Fireplaces CB36PTR - Page 21

20
EN
(H
T
) > (V
T
)
Simple venting configuration See graph to determine the required vertical rise V
T
for the
(only two 90° elbows) required horizontal run H
T
.
12.5 (3.8)
12.25 (3.7)
REQUIRED VERTICAL
RISE IN 8.3 (2.54)
FEET
(METERS)V
T
5.5
(1.68)
4.2 (1.3)
1
(0.3)
0
2.5
5
7.5
10
12.5
15
17.5
20
(0.8)
(1.5)
(2.3)
(3.1)
(3.8)
(4.6)
(5.3)
(6.1)
1
3.5
19.25
(0.3)
(1.1)
(5.9)
HORIZONTAL VENT RUN PLUS OFFSET IN FEET (METERS) H
T
The shaded area within the lines represents acceptable
values for H
T
and H
T
For vent configurations requiring more than two 90° elbows, the following formulas apply:
Formula 1: H
T
<
3.5V
T
Formula 2: H
T
+ V
T
<
24.75 feet (7.5m)
Example:
90°
V
1
= 4 FT (1.2m)
V
2
= 1.5 FT (0.5m)
H
3
V
T
= V
1
+ V
2
= 4FT (1.2m) + 1.5FT (0.5m) = 5.5 FT (1.7m)
H
1
= 2 FT (0.6m)
H
2
= 1 FT (0.3m)
90°
V
2
H
3
= 1 FT (0.3m)
H
4
= 1.5 FT (0.5m)
H
2
H
R
= H
1
+ H
2
+H
3
+H
4
= 2FT(0.6m) + 1FT(0.3m) + 1FT(0.3m) + 1.5FT(0.5m) = 5.5 FT(1.7m)
H
O
= .03 (four 90° elbows + one 45° elbow - 90°)
H
T
= .03 (90 + 90 + 90 + 90 + 45 - 90) = 9.45 FT (2.9m)
90°
= H
R
+ H
O
= 5.5FT (1.7m) + 9.45FT (2.9m) = 14.95FT (4.6m)
V
1
H
T
+ V
T
= 14.95FT (4.6m) + 5.5FT (1.7m) = 20.45FT (6.2m)
H
1
Formula 1:
H
T
<
3.5V
T
3.5V
T
= 3.5FT (1.1m) x 5.5FT (1.7m) = 19.25FT (5.9m)
90°
14.95 FT (4.6m) < 19.25 FT (5.9m)
Formula 2:
H
T
+ V
T
<
24.75 FT (7.5m)
20.45 FT (6.2m) < 24.75 FT (7.5m)
Since both formulas are met, this vent configuration is acceptable.
W415-1679 / D / 03.09.18