All~99991
Bl
1~99991
Let's look step by step
at
how the multiplication works. using the values of
AH. AL.
BH.
and
BL
from our example:
AH
1~99991
BH
1~99991
The first multiplication
is
BL
x AL;
~~
xêEI
~
89991
89991
89991
89991
99980001
The second multiplication
is
BL
x AH.
as
shown in the diagram below:
AH
1
9999
1
...........
ŒD
x
[]8]
Bl~
99980001
999800010000
Notice
that
P2
is
not
directly beneath
P1.
but
four spaces to the left (recall
the rules for Iining up the products of
2-digit
multiplication problems). To con-
tinue in the same manner. the third multiplication should
be
as
follows:
[AH]
Al
199991
BH~---[K]
999800010000
The fourth and final multiplication should
be
as
follows:
AH
1
9999
1)
ŒJ
BH~
ŒJ
9998000100000000
Remember that only the values of the four segments are multiplied;
this means
that
the actual multiplication done by AL x BH, etc. yields the
same number,
99980001,
for ail four products.
50,
in
the program the pro-
ducts are aligned by converting the products into strings and concatenating
the necessary number of zeros onto the end of the strings to align them pro-
perly.
This occurs in statements 1070 through 1100.
1070
P1$=STR$(BL*AL)
1080
P2$=STR$(BL*AH)+F$
1090
P3$=STR$(BH*AL)+F$
1100
P4$=STR$(BH*AH)+F$+F$
218
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