The LA102 results memories are split into compartments where each compartment can
hold one segment from each segment group listed below. Configuration C (in the LA102)
must be set to determine the number of compartments per memory, and the number of
memories. If insufficient compartments are available when a sequence is being received
then some segments will be lost and the LA102 will generate a Sequence Error 12 (not
enough compartments), followed by a
Sequence Error 8 (missed segments).
The possible settings for configuration C are:
Number of results memories
C1 1 compartment per memory and 6 memories (0-5)
C2 2 compartments per memory and 3 memories (0-2)
C3 3 compartments per memory and 2 memories (0-1)
C4 4 compartments per memory and 1 memory (0)
C5 5 compartments per memory and 1 memory (0)
One compartment can hold one segment from each of the following groups:
GROUP SEGMENTS
Frequency response: O P Q R S U X o r u x
Test level: T V
CCIR noise: M N
A weighted & O.41 noise: L n
Crosstalk and user levels: A B C J K
Miscellaneous: H c d h
Distortion: D F G I
Distortion: E
W&F and phase: W z
Phase: Y Z
Configuration C1 is the normal default setting with 1 compartment and 6 memories, the
same as earlier software, and this is suitable for all of the default sequences. Allowing
more compartments in each memory reduces the number of memories and the user must
decide the best compromise. If results memories are not being used at all configuration
C5 can be set to allow up to 5 segments from each group. Remember that memory 0 is
the working memory used to receive sequences and that another memory will be lost if
user tolerances are defined with configurations C1 to C3. Memory operations will show
the range of available memory numbers or give a warning message if no memories are
available. Changing configuration C will clear all results memories as the LA102
must reorganize its memory usage.
Only one source message segment (+) and one test level segment (T or V) is allowed in
each sequence. To find the number of compartments needed for a particular sequence,
examine the groups listed above and count the number of segments in each group (if the
same segment letter is used twice within a sequence it must be counted twice). The
maximum number of segments in any one group determines the minimum number of
compartments required to store the results (and hence the minimum value for
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4. User Defined Sequences
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