13 - 17
Chapter 13 Control Sub Functions
Thus, AP, AL and AM
to be set are as follows.
AP = 2883584 ……[Pr.2] AP = 2883584 ....... [Pr.2]
AL = 67.50000 ….[Pr.3] or AL = 0.06750 ........ [Pr.3]
AM = 1 ………..….[Pr.4] AM = 1000 ............. [Pr.4]
Note): These two examples of settings are only examples. There are
settings other than these examples.
(4) When "mm" is set as the control unit for conveyor drive
(calculation including
)
When the belt conveyor drive is used, the conveyor diameter is 135mm,
the pulley ratio is 1/3, the motor is HG-KR (4194304PLS/rev) and the
reduction ratio of the reduction gear is 7/53.
Reduction ratio 7/53
M
Belt
conveyor
Pulley ratio 1/3
135mm
As the travel value of the conveyor is used to exercise control, set "mm"
as the control unit.
First, find how many millimeters the load (machine) will travel (
S
) when
the motor turns one revolution (AP).
AP (Number of pulses per rotation) = 4194304 [PLS]
S
(Movement amount per rotation)
= 135000.0 [
m]
Reduction ratio
= 135000.0 [
m]
7/53
1/3
Substitute this for the above expression (1).
At this time, make calculation with the reduction ratio 7/53
1/3
remaining as a fraction.
AP
=
AP
=
4194304 [PLS]
S
AL
AM
135000.0 [
m]
7/53
1/3
=
4194304
53
3
135000.0
7
=
166723584
236250
Here, make calculation on the assumption that
is equal to
3.141592654.
AP
=
AP
=
166723584
S
AL
AM
742201.2645075
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