766 Appendix A: Functions and Instructions
ans() 2 ± key
ans() ⇒
value
ans(
integer
) ⇒
value
Returns a previous answer from the Home screen
history area.
integer
, if included, specifies which previous answer
to recall. Valid range for
integer
is from 1 to 99 and
cannot be an expression. Default is 1, the most
recent answer.
To use
ans()
to generate the Fibonacci
sequence on the Home screen, press:
1
¸ 1
1
¸ 1
2
±
«
2
±
A
0
2
¸ 2
¸ 3
¸ 5
approx() MATH/Algebra menu
approx(
expression
) ⇒
value
Returns the evaluation of
expression
as a decimal
value, when possible, regardless of the current
Exact/Approx
mode.
This is equivalent to entering
expression
and
pressing
¥
¸
on the Home screen.
approx(p)
¸ 3.141
...
approx(
list1
) ⇒
list
approx(
matrix1
) ⇒
matrix
Returns a list or matrix where each element has
been evaluated to a decimal value, when possible.
approx({sin(p),cos(p)})
¸
{0. ë1.}
approx([‡(2),‡(3)])
¸
[1.414
...
1.732
...
]
Archive CATALOG
Archive
var1
[,
var2
] [,
var3
] …
Moves the specified variables from RAM to the user
data archive memory.
You can access an archived variable the same as
you would a variable in RAM. However, you cannot
delete, rename, or store to an archived variable
because it is locked automatically.
To unarchive variables, use
Unarchiv
.
10!arctest ¸ 10
Archive arctest ¸ Done
5ùarctest ¸ 50
15!arctest ¸
N
Unarchiv arctest ¸ Done
15!arctest ¸ 15
arcLen() MATH/Calculus menu
arcLen(
expression1
,
var
,
start
,
end
) ⇒
expression
Returns the arc length of
expression1
from
start
to
end
with respect to variable
var
.
Regardless of the graphing mode, arc length is
calculated as an integral assuming a function mode
definition.
arcLen(cos(x),x,0,p)
¸ 3.820
...
arcLen(f(x),x,a,b)
¸
⌡
⌠
a
b
(
d
dx
(f(x)))ñ+1 dx
arcLen(
list1,var,start,end
) ⇒
list
Returns a list of the arc lengths of each element of
list1
from
start
to
end
with respect to
var
.
arcLen({sin(x),cos(x)},x,0,p)
{3.820
...
3.820
...
}
augment( ) MATH/Matrix menu
augment(
list1,
list2
) ⇒
list
Returns a new list that is
list2
appended to the end
of
list1
.
augment({1,ë3,2},{5,4})
¸
{1 ë3 2 5 4}
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