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Appendix A: Functions and Instructions 825

part(

expression1

) ⇒

expression

Simplifies

expression1

and returns the

argument

or operand, where

is > 0 and

the number of top-

level arguments or operands returned by

part(

expression1

)

. Otherwise, an error is returned.

part(cos(pù x+3),1) ¸ 3+pøx

Note: Simplification changed the order of the

argument.

By combining the variations of

part()

, you can

extract all of the sub-expressions in the simplified

result of

expression1

. As shown in the example to the

right, you can store an argument or operand and

then use

part()

to extract further sub-expressions.

Note: When using

part()

, do not rely on any

particular order in sums and products.

part(cos(pù x+3)) ¸ 1

part(cos(pù x+3),0) ¸ "cos"

part(cos(pù x+3),1)! temp ¸

3+pøx

temp ¸ pøx+3

part(temp,0) ¸ "+"

part(temp) ¸ 2

part(temp,2) ¸ 3

part(temp,1)! temp ¸ pøx

part(temp,0) ¸ "ù "

part(temp) ¸ 2

part(temp,1) ¸ p

part(temp,2) ¸ x

Expressions such as (x+y+z) and (x

z) are

represented internally as (x+y)+z and (x

This affects the values returned for the first and

second argument. There are technical reasons why

part(

x+y+z,1

)

returns y+x instead of x+y.

part(x+y+z) ¸ 2

part(x+y+z,2) ¸ z

part(x+y+z,1) ¸ y+x

Similarly, x

z is represented internally as

z. Again, there are technical reasons why

the first argument is returned as y

x instead of x

part(xù yù z) ¸ 2

part(xù yù z,2) ¸ z

part(xù yù z,1) ¸ yøx

When you extract sub-expressions from a matrix,

remember that matrices are stored as lists of lists,

as illustrated in the example to the right.

part([a,b,c;x,y,z],0) ¸ "{"

part([a,b,c;x,y,z]) ¸ 2

part([a,b,c;x,y,z],2)! temp

{x y z}

part(temp,0) ¸ "{"

part(temp) ¸ 3

part(temp,3) ¸ z

delVar temp ¸ Done

Brand	Texas Instruments
Model	TI-89 Titanium
Category	Calculator
Language	English

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