MODULE POWER REQUIREMENTS
SIZING THE MODULAR POWER SYSTEM
I-E96-508C B - 7
System Calculation Example Using IEPDS01 or IEPDS02 Power Modules Only
Assume that the current requirements for a set of modules
residing in a system cabinet have been calculated.
Additionally, the current requirements for 24 VDC I/O power
were calculated. The results are:
A = 26.5 amps (5 VDC cabinet requirement)
B = 3.1 amps (24 VDC I/O power requirement)
C = 0.9 amps (+15 VDC cabinet requirement)
D = 0.4 amps (-15 VDC cabinet requirement)
Substitute these values into the equations and solve for Q.
Q1 = (26.5/10) because B = 3.1 which is less than
A/5 = 26.5/5 = 5.3
Q1 = 2.65
Q2 = 0.9/0.5
Q2 = 1.8
Q3 = 0.4/0.5
Q3 = 0.8
QS = Largest value of Q1, Q2 and Q3
QS = 2.65
Round the value of QS to the next highest integer. This is the
number of PDS power modules required to power the system.
QS(N) = 3 PDS modules
With N+1 redundancy
QS(N+1) = QS(N) + 1 = 4 PDS modules
For Systems Using Both IEPDS01 and IEPDF01, or IEPDS02 and IEPDF02 Power Modules
Let:
A = total 5 VDC current requirements for system cabinet
B = total 24 VDC current requirements for associated I/O
C = total +15 VDC current requirements for system
cabinet
D = total -15 VDC current requirement for system cabinet
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