45 – Pvd3665_Gb_Ex_August 2022
Example n°1 :
The application needs:
- a rms torque of 7 Nm at the rms speed of 2000 rpm,
- an acceleration torque of 10 Nm,
- a maximal speed of 2800 rpm.
Selection of the motor:
The selected motor is the type EX620EAO.
The nominal speed is equals to 4300 rpm.
The maximal speed is equals to 4300 rpm.
The torque sensitivity is equals to 1.27 Nm/Arms.
The permanent current I
0
of the motor is 5.51 Arms for M
0
=7 Nm at low speed.
The nominal current I
n
of the motor is 2.46 Arms for M
n
= 3.13 Nm at the nominal speed.
Selection of the drive:
The drive has to provide at least a permanent current equals to I
0
(5.51 Arms).
In order to obtain an acceleration torque of 10 Nm, the current will be about 8 Arms. This means
that the drive has to provide at least 8 Arms as transient current.
→ Therefore, we can select the drive AC890SD-53 2100 B which delivers under 400 VAC:
6 Arms as permanent current and
6*200%=12 Arms as maximal transient current during 4 s.
The drive is set with “Servo Mode”.
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