46 – Pvd3665_Gb_Ex_August 2022
Example n°2 :
This times; the application needs :
- a permanent torque of 5 Nm at low speed,
- a rms torque of 5 Nm at the rms speed of 1890 rpm,
- an acceleration torque of 7.6 Nm,
- a maximal speed of 2800 rpm.
Selection of the motor:
The selected motor is the type EX620EAO.
The nominal speed is equals to 4300 rpm.
The maximal speed is equals to 4300 rpm.
The torque sensitivity is equals to 1.27 Nm/Arms.
Selection of the drive:
The drive has to provide a permanent current equals to 4 Arms to obtain 5 Nm.
In order to obtain an acceleration torque of 7.6 Nm, the current will be of about 6 Arms
This means that the drive has to provide at less 6 Arms as transient current.
Compared to the previous example n°1, it is now possible to decrease the size of drive.
→ Therefore, we can select the drive AC890SD-53 1600 B which delivers under 400 VAC:
4 Arms as permanent current and
4*200%=8 Arms as maximal transient current during 4 s.
The drive is set with “Servo Mode”.