User’s Manual
61
7. APPENDICES
7.1. APPLICATION NOTES
7.1.1. SIZING YOUR BRAKING REQUIREMENTS
Braking transistor modules are sized by peak current requirements and
system voltage. Please use the following guidelines:
Verify the amount of peak power needed for braking. This must be
determined from the mechanical system layout, and should be calculated
in either peak watts or horsepower.
VFD’s are rated for braking power as well as peak braking capacity. This
information is available in the drive manual. This will be the maximum
amount of power that the output inverter stage of the VFD can absorb
from the load before having an overcurrent condition. Refer to your VFD
documents for information on drive sizing. Keep in mind that the current
rating of the drive is for three phase current, not DC bus current. The
braking current in the DC bus will be higher than the AC current absorbed
from the load.
Because Bonitron braking transistor modules are rated for peak current,
determine the peak braking power required.
7.1.1.1. HORSEPOWER TO WATTS
Once the braking requirements for the mechanical load are determined,
multiply the horsepower by the scaling factor of 746 to determine the
wattage required. For instance, with a 400 HP system, the peak braking
power may be 600 hp. In this case the peak power required would be:
7.1.1.2. PEAK AMPERAGE
The peak amperage of the braking cycle can be determined by dividing
the peak braking wattage by the system bus trip point of the braking
transistor module used. If the above example were on a 480 VAC system,
the trip point is 750 VDC, as determined from Table 2-3: In this case the
peak current required would be:
In this case, a 600 Amp module should be used.
7.1.1.3. OHMIC VALUE
The ohmic value of the resistive load can usually be determined from the
Tables in Section 6-1. The ohmic value shown indicates the capacity of
the braking transistor module, and may not be directly related to the
horsepower of the drive. In order to calculate the required ohmic value
for the braking load, use the following formula:
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