20050401
kk
kk
k Quadratic Differential Calculations [OPTN]-[CALC]-[d
2
/dx
2
]
After displaying the function analysis menu, you can input quadratic differentials using the
following syntax.
K4(CALC)3(d
2
/dx
2
) f(x),a,tol)
Quadratic differential calculations produce an approximate differential value using the
following second order differential formula, which is based on Newton’s polynomial
interpretation.
2 f (a + 3h) – 27 f (a + 2h) + 270 f (a + h) – 490 f (a)+270 f(a – h) – 27 f (a – 2h) +2 f (a – 3h)
f''(a) = –––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––
180h
2
In this expression, values for “sufficiently small increments of h” are used to obtain a value
that approximates f ”(a).
○○○○○
Example To determine the quadratic differential coefficient at the point where
x = 3 for the function y = x
3
+ 4x
2
+ x – 6
Here we will use a tolerance tol = 1E – 5
Input the function f(x).
AK4(CALC)3(d
2
/dx
2
) vMd+
evx+v-g,
Input 3 as point a, which is the differential coefficient point.
d,
Input the tolerance value.
bE-f)
w
2-5-5
Numerical Calculations
(a: differential coefficient point , tol: tolerance)
d
2
d
2
––– (f (x), a) ⇒ ––– f (a)
dx
2
dx
2
# In the function f(x), only X can be used as a
variable in expressions. Other variables (A
through Z excluding X, r,
θ
) are treated as
constants, and the value currently assigned to
that variable is applied during the calculation.
# Input of the tolerance (tol) value and the closing
parenthesis can be omitted.
# Specify a tolerance (tol) value of 1
E-14 or greater.
An error (Time Out) occurs whenever no solution
that satisfies the tolerance value can be obtained.
20070101
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