Delta AH500 - Page 643

Chapter 6 Applied Instructions
6-475
API Instruction code Operand
Function
2111 $RIGHT P
S, n, D
The retrieve of the characters in the
string begins from the right.
Device
X Y M S T C HC D L SM SR E PR K 16# “$” DF
S
        
n
          
D
      
Pulse instruction
16-bit instruction (7-13 steps)
32-bit instruction
AH500
AH500
-
Symbol:
S
：
String Word
n
：
Number of characters which are
retrieved
Word
D
：
Device in which the characters
retrieved are stored
Word
Explanation:
1. The instruction is used to retrieve n characters in the string in S from the right, and the
characters which are retrieved are stored in D.
2. If n is 0, the value in D is 0.
b15
b0
b7
b8
16#00
S
+1
S
Second ASCII code from the last
First ASCII code from the last
.....................
~
~
Third ASCII code from the last
n-2 ASCII code from the last
th
n-3 ASCII code from the last
th
16#00
~
D
+1
D
.....................
First ASCII code
Second ASCII code
T
hird ASCII code
Fourth ASCII code
n-1 ASCII code from the last
th
n ASCII code from the last
th
n-1 ASCII code from the last
th
n ASCII code from the last
th
n-2 ASCII code from the last
th
n-3 ASCII code from the last
th
Third ASCII code from the last
First ASCII code from the last
Second ASCII code from the last
If the data in S is ABCDEF12345 and n is 5, five characters in the string in S are retrieved from
the right. The conversion result is as follows.
b15
b0
b7 b8
0016#
S
+1
S
+2
S
+3
S
16#41(A) 16#42(B)
43(C)16# 44(D)16#
46(F)16#
45(E)16#
31(1)16#
32(2)16#
34(4)16#
33(3)16#
+4
S
+5 S
35(5)16#
b15
b0
b7 b8
D
+1 D
+2 D
16#31(1) 32(2)16#
33(3)16# 34(4)16#
16#00
35(5)16#
The fifth character from the last
ABCDEF12345