S5-115F Manual STEP 5 Operations
ExplanationSTL
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L IW 35
L KH 00FF
OW
T IW 35
Load input word IW 35 into ACCUM 1.
Load a constant into ACCUM 1. The previous contents of ACCUM 1 are
shifted to ACCUM 2.
Combine the contents of both accumulators bit by bit through logic OR.
Transfer the result (contents of ACCUM 1) to input word IW 35.
Numeric Example
Set the 8 low-order bits in input
word IW 35 to ”1”. Compare both
words bit by bit.
If corresponding bits are both ”1”,
a ”1” is set in the result word.
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OR
Result
0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
15 0
1 1 1 0 0 1 0 0 1 1 1 1 1 1 1 1
1 1 1 0 0 1 0 0 1 1 0 0 0 1 1 0
KH 00FF
ACCUM 2
ACCUM 1
ACCUM 1
IW 35
EWA 4NEB 811 6149-02
3-47
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