4.10 Symmetric components
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Example 2, two phase injection with adjustable phase angle
U
N
= 100 V
Injection:
U
L1
= U
L1
= 100/3 V 0° = 57.7 V 0°
U
L2
= U
L2
= 100/3 V 120° = 57.7 V 120°
U
L3
= U
L3
= 0 V
This is actually identical case with example 2 because the
resulting line-to-line voltages U
L12
= U
L1
– U
L2
= 100 V 30°
and U
L23
= U
L2
– U
L3
= U
L2
= 100/3 V120° are the same as
in example 2. The only difference is a +30° phase angle
difference, but without any absolute angle reference this phase
angle difference is not seen by the device.
602.19
05.38
602.19
60100
0200
60100
33
1
1201000100
01000100
1201000100
33
1
0
120
3
100
0
3
100
1
1
111
3
1
2
2
2
1
0
aa
aa
U
U
U
U
0
= 19.2 %
U
1
= 38.5 %
U
2
= 19.2 %
U
2
/U
1
= 50 %
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