Expected result: start of the protection function and trip in zone 1 when trip conditions are fulfilled.
11.4.12.4 Test of the point SE (R
RvsR
, X
RvsX
)
GUID-335F54E6-52DE-4BF1-A34B-0C2DB8059CC1 v1
The trajectory of the impedance traverses the lens characteristic in zone 1
GUID-2DD20D2E-6188-4631-A584-5E68B212E011 v1
Preliminary steady state test at 50 Hz
GUID-7BCF3D7B-1B84-46D4-B9E3-066894A878E8 v1
• Go to Main menu /Test /Function status /Impedance protection /OutOfStep(78,Ucos) /
OOSPPAM(78,Ucos):1 /Outputs to check the available service values of the function block
OOSPPAM.
• Apply the following three-phase symmetrical quantities (the phase angle is related to phase L1):
V V
V
V
V
ts t RvsZ
VT s
VT p
= × × = × × =0 9 0 9 5899
0 1
13 8
38 47. .
.
.
.
,
,
,
EQUATION14067 V1 EN-US (Equation 61)
29.60
arctan 180 arctan 180 90.56
0.29
ts
ReverseX
V
ReverseR
Ð = - ° = - ° = - °
æ ö æ ö
ç ÷ ç ÷
è ø è ø
EQUATION14068 V1 EN-US (Equation 62)
frequency of V
ts
= 50 Hz
I I
I
I
A
s
CTs
CTp
50 50
10459
1
9000
1 162= × = × = .
EQUATION14059 V1 EN-US (Equation 63)
∠I
50s
= 0º
frequency of I
50s
= 50 Hz
It I
I
I
A
fs
CTs
CTp
tf= × = × =10459
1
9000
1 162.
EQUATION14062 V1 EN-US (Equation 64)
∠I
tfs
= 0º
frequency of I
tf
= 50 Hz
• Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are according to the injected
quantities and that ROTORANG is close to 3.14 rad. For this particular injection the service values
are:
• VOLTAGE = 5.31 kV
• CURRENT = 20918 A
• R = -0.26%
• X = -26.65%
• ROTORANG = -3.06 rad
Note that these values identify a point inside the lens characteristic in zone 1 that is close to the
point SE. The START is issued, but no TRIP is performed.
Execution of the dynamic test
GUID-FF6DCD5B-96AA-4255-8740-B85C8C7148F5 v1
The test may be performed by using two states of a sequence tool that is a basic feature of test sets.
• State 1: pre-test condition.
Section 11 1MRK 504 165-UUS Rev. J
Testing functionality by secondary injection
156 Transformer protection RET670
Commissioning manual
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