Lust CDA3000 - Example of Solution with Six-Pole Motor

2-8
Engineering Guide CDA3000
2 Drive definition
2.2.2 Example of
solution with
six-pole motor
Solution:
The rated power of the motor (six-pole) and the inverter is 30 kW.
Requirement:
n
1
= 150 rpm
n
2
= 1500 rpm
M
1
= M
2
= 150 Nm
External ventilation
not permitted.
Engine speeds
Continuous load characteristic in
inverter operation
2
2,5
3
4
5
6
7
8
9
10
15
20
25
30
40
50
60
70
80
90
100
P
N UR
[kW]
150
200
250
300
2
2,5
3
4
5
6
7
8
9
10
15
20
25
30
40
50
60
70
80
90
100
150
200
250
300
2
2,5
3
4
5
6
7
8
9
10
15
20
25
30
40
50
60
70
80
90
100
150
200
250
300
400
4
5
6
7
8
9
10
15
20
25
30
40
50
60
70
80
90
100
150
200
250
300
400
Rated power, inverter and motor
0,5
0,6 0,7 0,8
0,9 1,0
M
M
M UR
f [Hz]
10
20
30
40
50
60
70
80
90
100
750 rpm
8-pole
100
200
300
400
500
600
700
800
750
900
1000
1100
1200
1300
1400
1500
200
400
600
800
1000
1200
1400
1000 rpm
6-pole
1600
1800
2000
1500 rpm
4-pole
200
400
600
800
1000
1200
1400
1500
1600
1800
2000
2200
2400
2600
2800
3000
3000 rpm
2-pole
n [rpm]
500
1000
1500
2000
3000
2500
3500
4000
4500
5000
6000
5500
6
10
20
30
40
50
60
70
80
90
100
200
300
400
500
600
700
800
900
1000
2000
3000
4000
M
[Nm]
Load torque
1.
1.
2.
3.
4.
2.
5.
P >