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7−5. Stabilizing filter
This instrument prepares Stabilizing filter that can filter through digital filter strongly when
variable width for load is within the constant value and also when the condition is frozen for more
than a constant period.
7−5−1. What is stabilizing filter?
As for stabilizing filter, when the variation width of load is within the value set by Function
F−97 and also when the condition is continued for more than the set period by the Function
F−10, the digital filter for stabilizing filter set by the Function F−09 will become effective.
That is, digital filter is applied only when the load is stable more than a constant value and also
stabilizes the load than before.
7−5−2. Setting related with stabilizing filter
D Set the data to apply stabilizing filter with the Function F−97. The stabilizing filter width
per set value “n” can be obtained through the display conversion by using the following
formula.
[Data width of stabilizing filter]＝[Set value of F−97]×[Display increment value]
For example, when the setting of F−97 is “00010” and display increment value is “D=5”,
it will be as follows:
[Data width of stabilizing filter]＝10×5
＝50D
D Supervisory time on data width for stabilizing filter can be set with the Function F−10.
D Set the digital filter for stabilizing filter with the Function F−09.
D Averaged−out times for digital filter for stabilizing filter per set value “m” can be obtained
by the following formula.
[Averaged−out times for stabilizing filter]＝2
m＋7
For example, when the setting for Function for F−09 is “00001”, it will be as follows:
[Times of stabilizing filter]＝2
1+7
＝256 times
Moreover, when digital filter has set with Function F−04, averaged−out times will become
“Averaged−out times of stabilizing filter” and also will be “Averaged−out times” with the
Function F−04. (Refer to the paragraph 7−3−1.)
That is,
[Averaged−out times]
＝[Averaged−out times with F−04]×[Averaged−out times for stabilizing filter]
For example, setting for F−04 is “00033”, and setting for Function F−09 is “00001”,
they will be as follows:
[Averaged−out times]＝2
3＋1
×2
3＋1
×2
1+7
＝16×16×256
＝65536（times）
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