Motion commands
4.5 Circular interpolation types, (G2/G3, CIP, CT)
Fundamentals
Programming Manual, 11/2006, 6FC5398-1BP10-2BA0
133
Example of milling
The following program lines contain an example for each circular programming possibility.
The necessary dimensions are shown in the production drawing on the right.
;
,
-
<
r
N10 G0 G90 X133 Y44.48 S800 M3
;Approach starting point
N20 G17 G1 Z-5 F1000
;Tool infeed
N30 G2 X115 Y113.3 I-43 J25.52
;Circle end point, center point in
;incremental dimensions
Or
N30 G2 X115 Y113.3 I=AC(90) J=AC(70)
;Circle end point, center point in
;absolute dimensions
Or
N30 G2 X115 Y113.3 CR=-50
;Circle end point, circle radius
Or
N30 G2 AR=269.31 I-43 J25.52
;Opening angle, center point in
;incremental dimensions
Or
N30 G2 AR=269.31 X115 Y113.3
;Opening angle, circle end point
Or
N30 N30 CIP X80 Y120 Z-10
;Circle end point and intermediate point:
I1= IC(-85.35)J1=IC(-35.35) K1=-6
;Coordinates for all
;three geometry axes
N40 M30
;End of program
To Next Page
Loading...
