Sanding STS-752RC - Page 148

147

1
=
80
64
2
2
2
= 0.32 rad

deg

0.32

180
=18°20′06″


1
= -

2
3) Calculation of transition coordinates
 2 AN
....)
936021610
1(
642


 2 AE
....)
75601320423
(
753



32.0280 N
....)
936021610
1(
)32.0()32.0()32.0(
642

)
9360
40010734182.0
216
01048576.0
10
01024.0
1(64 
)00000011.000004855.001024.01(64 

64 * 0.98981

63.348
Similarly, the value of E is:
32.0280 E
....)
75601320423
32.0
(
)32.0()32.0()32.0(
753

)00000025.000078019.010666667.0(64 

6.777
This example is symmetry spiral transition N1=N2，E1=E2
4) Calculation of shift value
R
)cos1(   RER
18cos1(100777.6 R
°20′06″)

1.700
Symmetry spiral transition
RR
21

5) Calculation of Spiral Transition coordinate
 sinRN
N
m

=63.348-100sin18°20′06″=31.891
Symmetry spiral transition
NN
mm 21

6) Calculation of Tangent Distance
N
RRD
m
LALAec
LA
R
1
121
)cot()(cos)
2
tan( 
LA
111°55′47″，
sin
1
cos ec
,
tan
1
cot 

D
1
100 * tan(111°55′47″/ 2) +1.7(1 / sin111°55′47″)