Sanding STS-752RC - Page 150

149

32
cos TL
NN
IPEC

3
2
sin TL
EE
IPEC

2
(Bearing from IP1 to IP2) = 322°07′30.1″

3
(Bearing from IP2 to EP) = 57°59′40.6″

N
BC
1750 - 221.615 * cos322°07′30.1″ =1575.068 m

E
BC
1400 - 221.615 * sin322°07′30.1″ =1536.058 m

N
EC
1750 –(-221.615) * cos57°59′40.6″=1867.456 m

E
EC
1400 –(-221.615) * sin57°59′40.6″=1587.929 m
The calculated results display as below :
The coordinates and the distance are calculated as below ：
1) Compute the length of straight line
Straight line
BP·KA1=
543.545
)1050553.1574()000.1100872.1249(
22


m
straight line KA2·BC
005.166
)976.1637058.1536()032.1444068.1575(
22


m
straight line
EC·EP
084.250
)929.15871800()456.18672000(
22


m