frequency of V
ts
= 50 Hz
I I
I
I
A
s
CTs
CTp
50 50
10459
1
9000
1 162= × = × = .
EQUATION14059 V1 EN-US (Equation 55)
∠I
50s
= 0º
frequency of I
50s
= 50 Hz
It I
I
I
A
fs
CTs
CTp
tf= × = × =10459
1
9000
1 162.
EQUATION14062 V1 EN-US (Equation 56)
∠I
tfs
= 180º
frequency of I
tfs
= 49.5 Hz
Expected result: start of the protection function and trip in zone 1 when trip
conditions are fulfilled.
13.4.5.4 Test of the point SE (R
RvsR
, X
RvsX
)
GUID-335F54E6-52DE-4BF1-A34B-0C2DB8059CC1 v1
The trajectory of the impedance traverses the lens characteristic in zone
1
GUID-2DD20D2E-6188-4631-A584-5E68B212E011 v1
Preliminary steady state test at 50 Hz
GUID-7BCF3D7B-1B84-46D4-B9E3-066894A878E8 v1
• Go to Main menu/Test/Function status/Impedance protection/
OutOfStep(78,Ucos)/OOSPPAM(78,Ucos):1/Outputs to check the available
service values of the function block OOSPPAM.
• Apply the following three-phase symmetrical quantities (the phase angle is related
to phase L1):
V V
V
V
V
ts t RvsZ
VT s
VT p
= × × = × × =0 9 0 9 5899
0 1
13 8
38 47. .
.
.
.
,
,
,
EQUATION14067 V1 EN-US (Equation 57)
29.60
arctan 180 arctan 180 90.56
0.29
ts
ReverseX
V
ReverseR
Ð = - ° = - ° = - °
æ ö æ ö
ç ÷ ç ÷
è ø è ø
EQUATION14068 V1 EN-US (Equation 58)
frequency of V
ts
= 50 Hz
I I
I
I
A
s
CTs
CTp
50 50
10459
1
9000
1 162= × = × = .
EQUATION14059 V1 EN-US (Equation 59)
Section 13 1MRK 502 073-UUS A
Testing functionality by secondary injection
174 Generator protection REG670 2.2 ANSI and Injection equipment REX060, REX061, REX062
Commissioning manual