E-7
Electronics Verification
Example 2 (English units)
Fluid = Saturated Steam URV = 40000 lb/hr
Line size = 3 in. LRV= 0 lb/hr
Line press. = 500 psia
&
&
r (
Table D-2 on page D-4)
7HPSRS
°
) 'HQVLW\
r
OEFXIW
Viscosity = 0.017 cp
K-factor (compensated) = 10.678 (via HART communicator or AMS)
M = F(Hz) /(K C
17
)
/
^
&
r
`
=
^
(0.00207792/1.078)}
=
/
0.0019276)
= 19271.2 lb/hr
Therefore, an input frequency of 400 Hz represents a flow rate
of 19271.2 lb/hr in this application.
For a given input frequency, you may also determine the current
output. Use the example on page D-9 with an input frequency of 300
Hz:
URV= 40000 lb/hr LRV= 0 lb/hr F
in
(Hz) = 300.00
= 9.83 mA
Therefore, an input frequency of 300.00 Hz represents a current
output of 9.83 mA.
I
FHz
()
K
(
C
17
)
LRV–
URV LRV–
------------------------------------------------------
16
()
ÍÝ
ËÛ
+=
300 10.678 0.0019276
()
0–
40000 0–
---------------------------------------------------------------------------------
16
()
ÍÝ
ËÛ
4+
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