Emerson 8800C - SI Units

E-9
Electronics Verification
SI Units Example 1 (SI units)
Fluid = Water URV= 2000 lpm
Line size = 80 mm LRV= 0 lpm
Line press. = 700 kPagC
8
= 4.40287E-03 (from TableD-4 on pageD-5)
Temp op. = 60 °C
K-factor (compensated) = 10.772 (via HART communicator or AMS)
Q = F (Hz)/(K  C
8
)
= 80/(10.722  0.00440287)
= 1686.8 lpm
Therefore, an input frequency of 80.00 Hz represents a flow rate of
1686.8 lpm in this application.
For a given input frequency, you may also determine the current
output. Use the above example with an input frequency of 80.00 Hz:
URV= 2000 lpm LRV= 0 lpm F
in
(Hz) = 80.00
= 17.49 mA
Therefore, an input frequency of 80.00 Hz represents a current output
of 17.49 mA.
Example 2 (SI units)
Fluid = Saturated Steam URV = 3600 kg/hr
Line size = 80 mm LRV= 0 kg/hr
Line press.= 700 kPagC
16
= C
11
/ r ( from Table D-4 on page D-4)
Temp op. = 170 °C Density(
r ) = 4.169 kg/cu-mtr (oper)
Viscosity = 0.015 cp
K-factor (compensated) = 10.715 (via HART communicator or AMS)
M = F(Hz) /(K  C
16
)
= 650/{10.715  (C
11
/ r)}
= 650/{10.715  (0.0733811/4.169 )}
= 650/(10.715  0.017602 )
= 3446.4 kg/hr
Therefore, an input frequency of 650.00 Hz represents a flow rate of
3446.4 kg/hr in this application.
I
FHz
() KC
8
() LRV–
URV LRV–
-------------------------------------------------------------
16
()
Ý
Ü
Û
Í
Ì
Ë
4+=
80 10.772 0.00440287 () 0– 
2000 0–
---------------------------------------------------------------------------------
16
()
ÍÝ
ÌÜ
ËÛ
4+
=