STEP 5 Operations S5-95F
015
ExplanationSTL
L DW 2
SLW 3
T DW 3
Load the contents of data word DW2 into ACCU 1.
Shift the bit pattern in ACCU 1 three positions to the left.
Transfer the result (contents of ACCU 1) to data word DW3.
Numeric Example
The value 464
10
is stored in data
word DW2. Multiply this value by
2
3
=8. Do so by shifting the bit
pattern of DW2 in ACCU 1 three
positions to the left.
0 0 0 0 1 1 1 0 1 0 0 0 0 0 0 0
15 0
0 0 0 0 0 0 0 1
3712
10
ACCU 1
ACCU 1
464
10
(DW2)
1 1 0 1 0 0 0 0
SLW 3
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015
ExplanationSTL
L IW 124
SRW 4
T QW 126
Load the value of input word IW124 into ACCU 1.
Shift the bit pattern in ACCU 1 four positions to the right.
Transfer the result (contents of ACCU 1) to output word QW126.
Numeric Example
The value 352
10
is stored in IW124.
Shift the corresponding bit pattern in
ACCU 1 four positions to the right to
divide the value 352
10
by 2
4
= 16.
0 0 0 0 0 0 0 0 0 0 0 1 0 1 1 0
15 0
0 0 0 0 0 0 0 1
22
10
ACCU 1
ACCU 1
352
10
(IW124)
0 1 1 0 0 0 0 0
SRW 4
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8-48
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