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Peterbilt 220 - Figure B-3 Balanced Body Unloaded: Cgf 184.7 In. (4691.45 MM) from Front Axle; Figure B-4 Liftgate Example: Cgf 322.2 in (8183.9 MM) from Front Axle

Peterbilt 220
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B-5
Appendix B
Weight Distribution
Now we will calculate the distributed weight of van body that weighs 4825 pounds (2188.5 kg). Since an empty
van is very close to a uniform object, you can assume that the CG of the van body is at a point equal to half of the
BL.
Figure B-3. Balanced Body Unloaded: CGf 184.7 in. (4691.45 mm) from front axle.
When the body is mounted on the chassis, assume that the forward edge is positioned 4 inches (102 mm) be-
hind the back of the cab. This is equivalent to 17. 3 inches ( 439. 4 mm) behind the front axle. Therefore, the
CG of the body is located 72 inches plus half the body length from the front axle.
Use Equations 1 and 2 to calculate the distributed additional weight of the body:
Lr =
CGf
WB
X L
184.7
214
(4825) = 4164.4 lbs (1888.9 kg)
Lf = L - Lr 4825 4164.4 = 660.5 lbs (299.6 kg)
Adding a liftgate to the van body will present some interesting weight distribution results. We will add a 1455
pound (659.9 kg) liftgate to the end of the van body. The CG location of non-uniform objects, such as a liftgate,
must be provided by the equipment manufacturer. For our example, the liftgate manufacturer has provided in-
stallation information that indicates the liftgate CGf is located 322.2 in (8183.9 mm) behind the front axle.
Rear Liftgate Example
Figure B-4. Liftgate Example: CGf 322.2 in (8183.9 mm) from front axle.

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