Azbil JTD910S - Page 120

3-54
Chapter 3 Starting and Stopping this Device
Calculation example:
ρ: 0.9
ρ
0
: 1.0
l: 1500 mm
h: 250 mm
d: 2000 mm
would result in:
0% liquid level differential pressure
LRV = (250×0.9) - (2000×1.0) = -1775 mm H
2
O = -17.41 kPa
100% liquid level differential pressure
URV = (1500+250)×0.9 - (2000×1.0)
= -425 mm H
2
O = -4.168 kPa
Accordingly,
Low limit (LRV): -17.41 kPa
High limit (URV): -4.168 kPa
is the resulting range.