Connections
34
Building Technologies A6V10257473_b_en_--.doc
Fire Safety & Security Products 01.2010
7.6 Monitored control outputs
Five monitored control outputs are available on terminal blocks X7, X6 and X5 for
the connection of various devices.
Technical data for control outputs 1 to 3
- activation by reverse polarity (polarities indicated are “activated” polarities,
according to connected device, a diode can be necessary)
- line monitoring: 3.3 kΩ resistance connected at the end of the line
- protection: 1 AT fuse (F4 / F5 / F6)
Technical data for control outputs 4 and 5
- activation polarity is not reversed
- line monitoring: by calibration, within a range between 1 and 900 Ω
- protection: 2 AF fuse (F1 / F2)
Technical data common to the 5 control outputs
The maximum number of devices per output is determined by calculation, in 2
steps (see example below), depending on:
- minimum/maximum XC10 operating voltage = 22.5 V / 27.6 V
- nominal current consumption per device (@24V, see device technical data’s)
- minimum device operating voltage (see device technical data’s)
- protection fuse rating = 1 A or 2 A
- cable resistance (2x1.5 mm2 = 24.2 Ω / km, 2x2.5 mm2 = 14.8 Ω / km)
Calculation example for a device consuming 0.35 A at 24 V and having a
minimum operating voltage of 17 V:
1. From maximum system voltage (V
SYS
MAX
) in order to make sure that device
consumption does not exceed fuse rating.
– Device current consumption at V
SYS
MAX
= (27.6 x 0.35) ÷ 24 = 0.402 A
– Maximum number of devices: 0.402 A x n ≤ 1 A or 2 A
=> n ≤ 1 ÷ 0.402 ≤ 2.48, i.e. 2 devices (outputs 1 to 3)
=> n ≤ 2 ÷ 0.402 ≤ 4.96, i.e. 4 devices (outputs 4 and 5)
2. From minimum system voltage (V
SYS
MIN
) in order to make sure, that in spite of the
cable resistance voltage drop, device minimum operation voltage is respected:
– Device consumption at V
SYS
MIN
= (17 x 0.35) ÷ 24 = 0.248 A
– Maximum voltage drop = 22.5 - 17 = 5.5 V
– Maximum line resistance (outputs 1 to 3) = 5.5 ÷ (0.248 x 2) = 11.08 Ω
– Maximum line resistance (outputs 4 and 5) = 5.5 ÷ (0.248 x 4) = 5.54 Ω
– Maximum line length (1.5 mm
2
) = (11.08 x 1000) ÷ 24.2 = 456 meters (outputs
1 to 3), = (5.54 x 1000) ÷ 24.2 = 228 meters (outputs 4 and 5)
– Maximum line length (2.5 mm
2
) = (11.08 x 1000) ÷ 14.8 = 748 meters (outputs
1 to 3), = (5.54 x 1000) ÷ 14.8 = 374 meters (outputs 4 and 5)