DAF 95XF - Page 93

95XF series Inspection and adjustment
EXPLANATORY NOTES ON THE MAINTENANCE ACTIVITIES
3-33
3.25 INSPECTION AND ADJUSTMENT, LOAD-DEPENDENT CONTROL VALVE,
LEAF SUSPENSION
Explanatory notes on instruction plate
The instruction plate contains details of the axle
loads and output pressures; these correspond to
the order of the axles underneath the vehicle.
So “1” is the front axle, etc.
To check the load-dependent control valve, the
details on the instruction plate relating to the
“driven axle” are therefore vital.
1. Measure the rear axle load.
Note:
Vehicles equipped with a trailing axle with
leaf spring s hould be adjusted with the
trailing axle lowered. When adjusting the
ALR valve, take the weight of both axles.
2. Check the attachment of the control lever
and its ease of operation.
3. Also check whether the correct valve and
the c orrect springs have been fitted (for
information, see t he instruction plate).
4. Check length L of the control lever (see
instruction plate).
5. Connect pressure gauge (1) to the test
connection (1) of the load-dependent valve
and pressure gauge (2) to the test
connection on one of the spring-brake
cylinders (service-brake c onnection) of the
rear axle.
6. Make sure t hat the reservoir pressure
exceeds 6.5 bar.
M6045
MEEREGELVENTIEL EMPTY-LOAD VALVE LAST-LEER VENTIEL VALVE CHARGE-VIDE VALVOLA VUOTO-CARICO VALVULA VIDA-CARGA
ASLAST AXLE LOAD ACHSLAST CHARGE SOUS ESSIEU CARICO ASSE CARGA EJE
UITGESTUURDE DRUK DELIVERY PRESSURE AUSGESTEUERTER DRUCK PRESSION DELIVREE PRESSIONE USCITA PRESION DE SALIDA
G p2 BALGDRUK
PRESSURE BELLOWS BALG DRUCK PRESSION COUSSIN PRESS.CUSCINI ARIA PRESION FUELLES
p3
bar barx 10
4
N
AUTOM. LASTAFHANKELIJKE REMKRACHTREGELING
AUTOM. LOAD SENSING DEVICE
AUTOM LASTABHANGIGE BREMSKRAFT REGELINR.
DISPOSITIF DE CORRECTION AUTOM DE FREINAGE
REGOLATORE AUTOM. DELLA FORZA FRENANTE
REGULADOR AUTOM. DEL ESFUERZO DE FRENADA
1261660
TYPE - TIPO : FA
KNR BR 4452 p1= > 6.5 bar p4= 6.0 bar 0093778
21
2.0 2.5 3.0 4.0 5.0
10.0 11.0 11.5
21
1.7 1.9 2.2 2.9 3.5 5.5 5.8 6.0
4.4 4.5 4.6 4.9 5.2 5.9 6.0 6.0
0.20.4
p4
p1
L= 195 MM
G= 11.5
α= 15 2
p2
L
i = 1 : 1.5
3
2
L
1
M6106
5
 200424