Basic Electricity 1:16
CP 1 – Cathodic Protection Tester Course Manual
© NACE International, 2000
02/01/05
I
T
E
I1
I2
R2
I4
R4
IT
I3
R1
R3
+
Figure 1.8 Series and Parallel Circuits Combined
Given E = 20 V
R
1
= 5
R
2
= 4
R
3
= 2
R
4
= 0.95
First, reduce the parallel part of the circuit to a single resistance
using the same formula as shown for Figure 1.7:
Ω==
Ω
+
Ω
+
Ω
= 05.1
95.0
1
2
1
4
1
5
1
1
R
T
We now have an equivalent series circuit of two resistors, 1.05 Ω
and 0.95 Ω for a total resistance of 2.00 Ω.